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Product 48, difference 2

The product of two sisters' ages is 48 and their difference is 2. What is the sum of their ages?

Show the answer and the worked solution

Correct answer: B.

14

Worked solution

  1. Factor pairs of 48: (1, 48), (2, 24), (3, 16), (4, 12), (6, 8).
  2. The pair differing by 2 is 6 and 8.
  3. Sum = 14.

Answer: 14.

The idea

For small products, list factor pairs instead of solving a quadratic. Algebraically, (a + b)² = (a − b)² + 4ab = 4 + 192 = 196, so a + b = 14.

Shortcut. Two numbers 2 apart multiply to one less than the square of their mean: 48 + 1 = 49 = 7², so the ages are 6 and 8 and the sum is 2 × 7 = 14.

Common trap. 16 comes from grabbing the familiar factor pair 4 × 12 without checking the difference, which is 8, not 2.

Product 48, difference 2 — Aptitude Question

Product 48, difference 2: The product of two sisters' ages is 48 and their difference is 2. Answer and worked solution on CodeKairo.

Question

The product of two sisters' ages is 48 and their difference is 2. What is the sum of their ages?

Options

  1. 12
  2. 14
  3. 16
  4. 20
Show the answer and the worked solution

Correct answer: B. 14

Worked solution

  1. Factor pairs of 48: (1, 48), (2, 24), (3, 16), (4, 12), (6, 8).
  2. The pair differing by 2 is 6 and 8.
  3. Sum = 14.

Answer: 14.

The idea

For small products, list factor pairs instead of solving a quadratic. Algebraically, (a + b)² = (a − b)² + 4ab = 4 + 192 = 196, so a + b = 14.

Shortcut. Two numbers 2 apart multiply to one less than the square of their mean: 48 + 1 = 49 = 7², so the ages are 6 and 8 and the sum is 2 × 7 = 14.

Common trap. 16 comes from grabbing the familiar factor pair 4 × 12 without checking the difference, which is 8, not 2.

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