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Looking back eight years

The present ages of two people are in the ratio 3 : 4. Eight years ago they were in the ratio 2 : 3. What is the sum of their present ages?

Show the answer and the worked solution

Correct answer: C.

56

Worked solution

  1. (3x − 8)/(4x − 8) = 2/3 → 9x − 24 = 8x − 16 → x = 8.
  2. Ages are 24 and 32; sum = 56.
  3. Check: sixteen and twenty-four eight years ago, ratio 2 : 3. ✓

Answer: 56.

The idea

Subtract the years from both terms for a past ratio. The question asks for the sum, so remember to add at the end.

Shortcut. Both ratios have a one-part gap, so the part size is unchanged between them: 3x − 8 = 2x → x = 8, and the sum is 7x = 56.

Common trap. 42 looks right because 18 and 24 reduce to exactly 3 : 4, but every option is a multiple of 7 and fits the present ratio; eight years back 42 gives 10 : 16 = 5 : 8, not 2 : 3.

Looking back eight years — Aptitude Question

Looking back eight years: The present ages of two people are in the ratio 3 : 4. Eight years ago they were in the… Answer and worked solution on CodeKairo.

Question

The present ages of two people are in the ratio 3 : 4. Eight years ago they were in the ratio 2 : 3. What is the sum of their present ages?

Options

  1. 42
  2. 49
  3. 56
  4. 63
Show the answer and the worked solution

Correct answer: C. 56

Worked solution

  1. (3x − 8)/(4x − 8) = 2/3 → 9x − 24 = 8x − 16 → x = 8.
  2. Ages are 24 and 32; sum = 56.
  3. Check: sixteen and twenty-four eight years ago, ratio 2 : 3. ✓

Answer: 56.

The idea

Subtract the years from both terms for a past ratio. The question asks for the sum, so remember to add at the end.

Shortcut. Both ratios have a one-part gap, so the part size is unchanged between them: 3x − 8 = 2x → x = 8, and the sum is 7x = 56.

Common trap. 42 looks right because 18 and 24 reduce to exactly 3 : 4, but every option is a multiple of 7 and fits the present ratio; eight years back 42 gives 10 : 16 = 5 : 8, not 2 : 3.

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