Repeated letters in a code — Aptitude Question
Repeated letters in a code: If RIPPLE is written as 613382 and LIFE as 8192, how is PILLER written? Answer and worked solution on CodeKairo.
- Topic: Coding & Decoding
- Section: Logical Reasoning
- Difficulty: Hard
- Time target: 120 seconds
Question
If RIPPLE is written as 613382 and LIFE as 8192, how is PILLER written?
Options
- 318286
- 318826
- 318862
- 381826
Show the answer and the worked solution
Correct answer: B. 318826
Worked solution
- RIPPLE → 613382: R=6, I=1, P=3, P=3, L=8, E=2.
- LIFE → 8192: L=8 ✓, I=1 ✓, F=9, E=2 ✓.
- PILLER = P,I,L,L,E,R = 3,1,8,8,2,6 = 318826.
Answer: 318826.
The idea
Repeated letters anchor the mapping: the doubled digit in the code must sit where the doubled letter sits in the word.
Shortcut. PILLER begins with RIPPLE's P and I (3, 1) and ends with R (6), so the code is 31 _ 6 — this removes 318862 and 381826. The middle L, L, E = 8, 8, 2 then picks 318826 over 318286.
Common trap. "318862" — reversing the last two letters, as if the word ended in RE like RIPPLE's LE; PILLER ends E then R, so 2 then 6.