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Hardset theory

~90s

Delegates at a conference

A conference had 800 delegates. 45% attended the morning session and 60% the afternoon session, while 25% attended both.

How many attended neither session?

Show the answer and the worked solution

Correct answer: C.

160

Worked solution

  1. At least one session = 45 + 60 − 25 = 80% of delegates.
  2. Neither = 20% of 800 = 160.

Answer: 160.

The idea

Work in percentages until the final step, then convert once. Subtracting the overlap is what keeps the union below 100%.

Shortcut. Neither = both − (A + B − 100): the two sessions sum to 105%, overshooting by 5, so neither = 25 − 5 = 20% of 800 = 160.

Common trap. 120 — subtracting only the afternoon 60% and the 25% overlap from 100% (15%), forgetting the 20% who attended the morning alone.

Delegates at a conference — Caselets Aptitude Question

Delegates at a conference: A conference had 800 delegates. 45% attended the morning session and 60% the afternoon… Answer and worked solution on CodeKairo.

Question

A conference had 800 delegates. 45% attended the morning session and 60% the afternoon session, while 25% attended both.

How many attended neither session?

Options

  1. 120
  2. 140
  3. 160
  4. 180
Show the answer and the worked solution

Correct answer: C. 160

Worked solution

  1. At least one session = 45 + 60 − 25 = 80% of delegates.
  2. Neither = 20% of 800 = 160.

Answer: 160.

The idea

Work in percentages until the final step, then convert once. Subtracting the overlap is what keeps the union below 100%.

Shortcut. Neither = both − (A + B − 100): the two sessions sum to 105%, overshooting by 5, so neither = 25 − 5 = 20% of 800 = 160.

Common trap. 120 — subtracting only the afternoon 60% and the 25% overlap from 100% (15%), forgetting the 20% who attended the morning alone.

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