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Doubling under compound interest

A sum doubles in 5 years at compound interest. In how many years will it become eight times itself?

Show the answer and the worked solution

Correct answer: B.

15

Worked solution

  1. Eight times = 2³, that is three successive doublings.
  2. Each doubling takes 5 years, so 3 × 5 = 15 years.

Answer: 15.

The idea

Under compound interest the multiples are powers, not multiples: doubling in t years gives 4× in 2t and 8× in 3t. Under simple interest the answer would be 35 years.

Shortcut. Chain the doublings — 1 → 2 by year 5, 2 → 4 by year 10, 4 → 8 by year 15 — instead of scaling the multiple.

Common trap. 20 — counting 8 ÷ 2 = 4 doublings; 8 is 2³, so three doublings of 5 years each.

Doubling under compound interest — Aptitude Question

Doubling under compound interest: A sum doubles in 5 years at compound interest. In how many years will it become… Answer and worked solution on CodeKairo.

Question

A sum doubles in 5 years at compound interest. In how many years will it become eight times itself?

Options

  1. 10
  2. 15
  3. 20
  4. 25
Show the answer and the worked solution

Correct answer: B. 15

Worked solution

  1. Eight times = 2³, that is three successive doublings.
  2. Each doubling takes 5 years, so 3 × 5 = 15 years.

Answer: 15.

The idea

Under compound interest the multiples are powers, not multiples: doubling in t years gives 4× in 2t and 8× in 3t. Under simple interest the answer would be 35 years.

Shortcut. Chain the doublings — 1 → 2 by year 5, 2 → 4 by year 10, 4 → 8 by year 15 — instead of scaling the multiple.

Common trap. 20 — counting 8 ÷ 2 = 4 doublings; 8 is 2³, so three doublings of 5 years each.

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