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Doubling under simple interest

At what rate of simple interest does a sum double itself in 8 years?

Show the answer and the worked solution

Correct answer: C.

12.5%

Worked solution

  1. To double, SI must equal P, so R × T = 100.
  2. R = 100 ÷ 8 = 12.5%.

Answer: 12.5%.

The idea

Under simple interest a sum becomes n times itself when R × T = 100(n − 1). Doubling gives 100, tripling 200.

Shortcut. Doubling means the interest equals P, so each of the 8 years must earn 1/8 of P — and 1/8 = 12.5%.

Common trap. 12% — truncating 100 ÷ 8 to a whole number; 12% for 8 years is only 96%, just short of doubling.

Doubling under simple interest — Aptitude Question

Doubling under simple interest: At what rate of simple interest does a sum double itself in 8 years? Answer and worked solution on CodeKairo.

Question

At what rate of simple interest does a sum double itself in 8 years?

Options

  1. 10%
  2. 12%
  3. 12.5%
  4. 15%
Show the answer and the worked solution

Correct answer: C. 12.5%

Worked solution

  1. To double, SI must equal P, so R × T = 100.
  2. R = 100 ÷ 8 = 12.5%.

Answer: 12.5%.

The idea

Under simple interest a sum becomes n times itself when R × T = 100(n − 1). Doubling gives 100, tripling 200.

Shortcut. Doubling means the interest equals P, so each of the 8 years must earn 1/8 of P — and 1/8 = 12.5%.

Common trap. 12% — truncating 100 ÷ 8 to a whole number; 12% for 8 years is only 96%, just short of doubling.

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