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Hardsurdsalgebra

~150s

Value of a surd expression

If x = 1/(2 − √3), find the value of x³ − 2x² − 7x + 5.

Show the answer and the worked solution

Correct answer: C.

3

Worked solution

  1. x = 1/(2 − √3) × (2 + √3)/(2 + √3) = (2 + √3)/(4 − 3) = 2 + √3.
  2. Then x − 2 = √3, so squaring gives x² − 4x + 4 = 3, i.e. x² − 4x + 1 = 0.
  3. Divide: x³ − 2x² − 7x + 5 = (x² − 4x + 1)(x + 2) + 3.
  4. The first term vanishes, leaving 3.

Answer: 3.

The idea

Rationalise, then convert the surd into a quadratic the variable satisfies. Reducing the higher polynomial by that quadratic avoids ever cubing a surd, which is where the arithmetic normally breaks down.

Shortcut. Estimate: x = 2 + √3 ≈ 3.732, so x² ≈ 13.93 and x³ ≈ 51.98. Then 51.98 − 27.86 − 26.12 + 5 ≈ 3.00, and every option is a whole number.

Common trap. 5 — assuming x² − 4x + 1 = 0 wipes out every x term and leaves the constant; (x² − 4x + 1)(x + 2) = x³ − 2x² − 7x + 2, which uses up 2 of the 5.

Value of a surd expression — Number System Aptitude Question

Value of a surd expression: If x = 1/(2 − √3), find the value of x³ − 2x² − 7x + 5. Answer and worked solution on CodeKairo.

Question

If x = 1/(2 − √3), find the value of x³ − 2x² − 7x + 5.

Options

  1. 1
  2. 2
  3. 3
  4. 5
Show the answer and the worked solution

Correct answer: C. 3

Worked solution

  1. x = 1/(2 − √3) × (2 + √3)/(2 + √3) = (2 + √3)/(4 − 3) = 2 + √3.
  2. Then x − 2 = √3, so squaring gives x² − 4x + 4 = 3, i.e. x² − 4x + 1 = 0.
  3. Divide: x³ − 2x² − 7x + 5 = (x² − 4x + 1)(x + 2) + 3.
  4. The first term vanishes, leaving 3.

Answer: 3.

The idea

Rationalise, then convert the surd into a quadratic the variable satisfies. Reducing the higher polynomial by that quadratic avoids ever cubing a surd, which is where the arithmetic normally breaks down.

Shortcut. Estimate: x = 2 + √3 ≈ 3.732, so x² ≈ 13.93 and x³ ≈ 51.98. Then 51.98 − 27.86 − 26.12 + 5 ≈ 3.00, and every option is a whole number.

Common trap. 5 — assuming x² − 4x + 1 = 0 wipes out every x term and leaves the constant; (x² − 4x + 1)(x + 2) = x³ − 2x² − 7x + 2, which uses up 2 of the 5.

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