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Diluting a salt solution

80 kg of a solution contains 15% salt by weight. How much water must be added so that the salt content falls to 10%?

Show the answer and the worked solution

Correct answer: C.

40 kg

Worked solution

  1. Salt = 15% of 80 = 12 kg, and this stays fixed.
  2. For 12 kg to be 10% of the mixture, the new total = 12 ÷ 0.10 = 120 kg.
  3. Water to add = 120 − 80 = 40 kg.

Answer: 40 kg.

The idea

In dilution the solute is constant. Divide it by the target concentration to get the new total, then subtract the old total.

Shortcut. Strength × total stays constant: strength falls from 15 to 10 (× 2/3), so the total rises × 3/2, from 80 to 120 kg — 40 kg of water.

Common trap. "30 kg" — cutting the strength by a third tempts adding about a third of 80 kg (≈ 26.7) and taking the nearest option; the total must grow by half.

Diluting a salt solution — Percentages Aptitude Question

Diluting a salt solution: 80 kg of a solution contains 15% salt by weight. How much water must be added so that the… Answer and worked solution on CodeKairo.

Question

80 kg of a solution contains 15% salt by weight. How much water must be added so that the salt content falls to 10%?

Options

  1. 20 kg
  2. 30 kg
  3. 40 kg
  4. 50 kg
Show the answer and the worked solution

Correct answer: C. 40 kg

Worked solution

  1. Salt = 15% of 80 = 12 kg, and this stays fixed.
  2. For 12 kg to be 10% of the mixture, the new total = 12 ÷ 0.10 = 120 kg.
  3. Water to add = 120 − 80 = 40 kg.

Answer: 40 kg.

The idea

In dilution the solute is constant. Divide it by the target concentration to get the new total, then subtract the old total.

Shortcut. Strength × total stays constant: strength falls from 15 to 10 (× 2/3), so the total rises × 3/2, from 80 to 120 kg — 40 kg of water.

Common trap. "30 kg" — cutting the strength by a third tempts adding about a third of 80 kg (≈ 26.7) and taking the nearest option; the total must grow by half.

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