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Mediumsuccessive change

~60s

Working back through two changes

A number is increased by 20% and then decreased by 20%, giving 9,600. What was the original number?

Show the answer and the worked solution

Correct answer: C.

10,000

Worked solution

  1. Net factor = 1.2 × 0.8 = 0.96.
  2. 0.96 × original = 9,600, so original = 9,600 ÷ 0.96 = 10,000.
  3. Check: 10,000 → 12,000 → 9,600. ✓

Answer: 10,000.

The idea

Collapse the chain of changes into one multiplier, then divide the final value by it. Reversing the steps one at a time works too but invites sign errors.

Shortcut. The net effect is a 4% loss, so the original must exceed 9,600, and 4% of 10,000 is exactly 400 (10,000 − 400 = 9,600).

Common trap. "9,216" — applying the 0.96 factor to 9,600 a second time (multiplying) instead of dividing by it.

Working back through two changes — Aptitude Question

Working back through two changes: A number is increased by 20% and then decreased by 20%, giving 9,600. Answer and worked solution on CodeKairo.

Question

A number is increased by 20% and then decreased by 20%, giving 9,600. What was the original number?

Options

  1. 9,216
  2. 9,800
  3. 10,000
  4. 10,400
Show the answer and the worked solution

Correct answer: C. 10,000

Worked solution

  1. Net factor = 1.2 × 0.8 = 0.96.
  2. 0.96 × original = 9,600, so original = 9,600 ÷ 0.96 = 10,000.
  3. Check: 10,000 → 12,000 → 9,600. ✓

Answer: 10,000.

The idea

Collapse the chain of changes into one multiplier, then divide the final value by it. Reversing the steps one at a time works too but invites sign errors.

Shortcut. The net effect is a 4% loss, so the original must exceed 9,600, and 4% of 10,000 is exactly 400 (10,000 − 400 = 9,600).

Common trap. "9,216" — applying the 0.96 factor to 9,600 a second time (multiplying) instead of dividing by it.

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