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Mediumgrowth

~60s

Population two years ago

The population of a town is 176,400 and grows at 5% per annum. What was it two years ago?

Show the answer and the worked solution

Correct answer: B.

1,60,000

Worked solution

  1. 1.05² = 1.1025.
  2. Population two years ago = 176,400 ÷ 1.1025 = 1,60,000.
  3. Check: 160,000 → 168,000 → 176,400. ✓

Answer: 1,60,000.

The idea

Growth forwards multiplies; going backwards divides. Subtracting 10% from the present figure is not the inverse of two 5% rises.

Shortcut. Check the options forwards: 1,60,000 × 1.05 = 1,68,000, then × 1.05 = 1,76,400 — an exact match, no division by 1.1025 needed.

Common trap. "1,68,000" — going back only one year (176,400 ÷ 1.05) and stopping there.

Population two years ago — Percentages Aptitude Question

Population two years ago: The population of a town is 176,400 and grows at 5% per annum. What was it two years ago? Answer and worked solution on CodeKairo.

Question

The population of a town is 176,400 and grows at 5% per annum. What was it two years ago?

Options

  1. 1,50,000
  2. 1,60,000
  3. 1,64,000
  4. 1,68,000
Show the answer and the worked solution

Correct answer: B. 1,60,000

Worked solution

  1. 1.05² = 1.1025.
  2. Population two years ago = 176,400 ÷ 1.1025 = 1,60,000.
  3. Check: 160,000 → 168,000 → 176,400. ✓

Answer: 1,60,000.

The idea

Growth forwards multiplies; going backwards divides. Subtracting 10% from the present figure is not the inverse of two 5% rises.

Shortcut. Check the options forwards: 1,60,000 × 1.05 = 1,68,000, then × 1.05 = 1,76,400 — an exact match, no division by 1.1025 needed.

Common trap. "1,68,000" — going back only one year (176,400 ÷ 1.05) and stopping there.

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