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Mediumcombinations

~60s

A committee of three

In how many ways can a committee of 3 people be chosen from 5 men and 4 women so that it has exactly 2 men?

Show the answer and the worked solution

Correct answer: B.

40

Worked solution

  1. Ways to choose 2 men from 5 = C(5,2) = 10.
  2. Ways to choose 1 woman from 4 = C(4,1) = 4.
  3. Total = 10 × 4 = 40.

Answer: 40.

The idea

Independent choices multiply. Selection uses combinations because the order within a committee does not matter.

Shortcut. C(5,2) is the handshake count for 5 people, 10, and exactly two men leaves one seat for any of the 4 women: 10 × 4 = 40.

Common trap. "84" — computing C(9,3), every committee of 3 from the 9 people, and dropping the 'exactly 2 men' condition.

Permutations & Combinations

11 of 35

Level

Medium

Target time

~60s

A committee of three — Aptitude Question

A committee of three: In how many ways can a committee of 3 people be chosen from 5 men and 4 women so that it has… Answer and worked solution on CodeKairo.

Question

In how many ways can a committee of 3 people be chosen from 5 men and 4 women so that it has exactly 2 men?

Options

  1. 30
  2. 40
  3. 60
  4. 84
Show the answer and the worked solution

Correct answer: B. 40

Worked solution

  1. Ways to choose 2 men from 5 = C(5,2) = 10.
  2. Ways to choose 1 woman from 4 = C(4,1) = 4.
  3. Total = 10 × 4 = 40.

Answer: 40.

The idea

Independent choices multiply. Selection uses combinations because the order within a committee does not matter.

Shortcut. C(5,2) is the handshake count for 5 people, 10, and exactly two men leaves one seat for any of the 4 women: 10 × 4 = 40.

Common trap. "84" — computing C(9,3), every committee of 3 from the 9 people, and dropping the 'exactly 2 men' condition.

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