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A ratio that changes with time

The present ages of two people are in the ratio 4 : 5. After 5 years the ratio becomes 5 : 6. What is the present age of the younger?

Show the answer and the worked solution

Correct answer: B.

20

Worked solution

  1. (4x + 5)/(5x + 5) = 5/6 → 24x + 30 = 25x + 25 → x = 5.
  2. The younger is 4x = 20.

Answer: 20.

The idea

Add the same number of years to both terms and cross-multiply. The difference between the two ages never changes, which is a quick sanity check on the answer.

Shortcut. The age gap is 1 part in both ratios, so a part is the same size before and after; 5 years moved the younger from 4 parts to 5, so 1 part = 5 years and the younger is 20.

Common trap. "25" — the younger's age five years from now (or the elder's today), not the younger's present age.

A ratio that changes with time — Aptitude Question

A ratio that changes with time: The present ages of two people are in the ratio 4 : 5. After 5 years the ratio… Answer and worked solution on CodeKairo.

Question

The present ages of two people are in the ratio 4 : 5. After 5 years the ratio becomes 5 : 6. What is the present age of the younger?

Options

  1. 16
  2. 20
  3. 24
  4. 25
Show the answer and the worked solution

Correct answer: B. 20

Worked solution

  1. (4x + 5)/(5x + 5) = 5/6 → 24x + 30 = 25x + 25 → x = 5.
  2. The younger is 4x = 20.

Answer: 20.

The idea

Add the same number of years to both terms and cross-multiply. The difference between the two ages never changes, which is a quick sanity check on the answer.

Shortcut. The age gap is 1 part in both ratios, so a part is the same size before and after; 5 years moved the younger from 4 parts to 5, so 1 part = 5 years and the younger is 20.

Common trap. "25" — the younger's age five years from now (or the elder's today), not the younger's present age.

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