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Temperatures across four days

The average temperature for Monday, Tuesday and Wednesday was 37°, and for Tuesday, Wednesday and Thursday it was 34°. If Thursday's temperature was 4/5 of Monday's, what was Monday's temperature?

Show the answer and the worked solution

Correct answer: D.

45°

Worked solution

  1. Mon + Tue + Wed = 3 × 37 = 111.
  2. Tue + Wed + Thu = 3 × 34 = 102.
  3. Subtracting: Mon − Thu = 9.
  4. Thu = (4/5)Mon, so Mon − 0.8Mon = 9 → 0.2Mon = 9 → Mon = 45°.

Answer: 45°.

The idea

Overlapping windows: subtract the two totals so the shared days cancel and only the two end days remain. Then use the given relation between them.

Shortcut. The two totals differ by 3 × (37 − 34) = 9, which is Monday − Thursday = Monday ÷ 5, so Monday = 45°.

Common trap. "36°" — solving correctly but reporting Thursday's temperature (4/5 × 45) instead of Monday's.

Temperatures across four days — Averages Aptitude Question

Temperatures across four days: The average temperature for Monday, Tuesday and Wednesday was 37°, and for Tuesday,… Answer and worked solution on CodeKairo.

Question

The average temperature for Monday, Tuesday and Wednesday was 37°, and for Tuesday, Wednesday and Thursday it was 34°. If Thursday's temperature was 4/5 of Monday's, what was Monday's temperature?

Options

  1. 36°
  2. 38°
  3. 40°
  4. 45°
Show the answer and the worked solution

Correct answer: D. 45°

Worked solution

  1. Mon + Tue + Wed = 3 × 37 = 111.
  2. Tue + Wed + Thu = 3 × 34 = 102.
  3. Subtracting: Mon − Thu = 9.
  4. Thu = (4/5)Mon, so Mon − 0.8Mon = 9 → 0.2Mon = 9 → Mon = 45°.

Answer: 45°.

The idea

Overlapping windows: subtract the two totals so the shared days cancel and only the two end days remain. Then use the given relation between them.

Shortcut. The two totals differ by 3 × (37 − 34) = 9, which is Monday − Thursday = Monday ÷ 5, so Monday = 45°.

Common trap. "36°" — solving correctly but reporting Thursday's temperature (4/5 × 45) instead of Monday's.

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