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Hardweighted average

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Technicians and the rest

The average salary of all workers in a workshop is ₹8,000. The average of 7 technicians is ₹12,000 and of the remaining workers ₹6,000. How many workers are there in all?

Show the answer and the worked solution

Correct answer: C.

21

Worked solution

  1. 84,000 + 6,000(n − 7) = 8,000n.
  2. 84,000 + 6,000n − 42,000 = 8,000n → 42,000 = 2,000n.
  3. n = 21.
  4. Check: 7 × 12,000 + 14 × 6,000 = 84,000 + 84,000 = 1,68,000 = 21 × 8,000. ✓

Answer: 21.

The idea

Set the sum of the group totals equal to the overall total and solve for the unknown count. Alligation gives the same answer faster: the ratio of technicians to others is (8,000 − 6,000) : (12,000 − 8,000) = 1 : 2.

Shortcut. Balance the surplus: 7 technicians are ₹4,000 above ₹8,000 (₹28,000 in all) and each other worker is ₹2,000 below, so 14 others are needed — 21 in all.

Common trap. "20" — a round total that nearly balances: 7 technicians and 13 others average (84,000 + 78,000) ÷ 20 = ₹8,100, just above ₹8,000.

Technicians and the rest — Averages Aptitude Question

Technicians and the rest: The average salary of all workers in a workshop is ₹8,000. The average of 7 technicians… Answer and worked solution on CodeKairo.

Question

The average salary of all workers in a workshop is ₹8,000. The average of 7 technicians is ₹12,000 and of the remaining workers ₹6,000. How many workers are there in all?

Options

  1. 18
  2. 20
  3. 21
  4. 24
Show the answer and the worked solution

Correct answer: C. 21

Worked solution

  1. 84,000 + 6,000(n − 7) = 8,000n.
  2. 84,000 + 6,000n − 42,000 = 8,000n → 42,000 = 2,000n.
  3. n = 21.
  4. Check: 7 × 12,000 + 14 × 6,000 = 84,000 + 84,000 = 1,68,000 = 21 × 8,000. ✓

Answer: 21.

The idea

Set the sum of the group totals equal to the overall total and solve for the unknown count. Alligation gives the same answer faster: the ratio of technicians to others is (8,000 − 6,000) : (12,000 − 8,000) = 1 : 2.

Shortcut. Balance the surplus: 7 technicians are ₹4,000 above ₹8,000 (₹28,000 in all) and each other worker is ₹2,000 below, so 14 others are needed — 21 in all.

Common trap. "20" — a round total that nearly balances: 7 technicians and 13 others average (84,000 + 78,000) ÷ 20 = ₹8,100, just above ₹8,000.

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