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Hardpythagoras

~120s

Two buses in opposite quadrants

Two buses leave the same depot. One goes 30 km north then 40 km east; the other goes 40 km south then 30 km west. How far apart are they?

Show the answer and the worked solution

Correct answer: B.

70√2 km

Worked solution

  1. First bus ends at (40, 30); second at (−30, −40).
  2. Differences: 70 east–west and 70 north–south.
  3. Distance = √(70² + 70²) = 70√2 km (about 98.99 km).

Answer: 70√2 km.

The idea

Coordinates are safer than sketching once the paths bend more than once. Sum each axis, then apply Pythagoras to the differences.

Shortcut. East–west gap = 40 + 30 = 70 and north–south gap = 30 + 40 = 70; equal gaps make a square's diagonal, 70√2 km (≈ 99).

Common trap. "100 km" — seeing each bus 50 km from the depot (3-4-5) and adding 50 + 50, which assumes they went in exactly opposite directions.

Two buses in opposite quadrants — Aptitude Question

Two buses in opposite quadrants: Two buses leave the same depot. One goes 30 km north then 40 km east; the other… Answer and worked solution on CodeKairo.

Question

Two buses leave the same depot. One goes 30 km north then 40 km east; the other goes 40 km south then 30 km west. How far apart are they?

Options

  1. 70 km
  2. 70√2 km
  3. 100 km
  4. 140 km
Show the answer and the worked solution

Correct answer: B. 70√2 km

Worked solution

  1. First bus ends at (40, 30); second at (−30, −40).
  2. Differences: 70 east–west and 70 north–south.
  3. Distance = √(70² + 70²) = 70√2 km (about 98.99 km).

Answer: 70√2 km.

The idea

Coordinates are safer than sketching once the paths bend more than once. Sum each axis, then apply Pythagoras to the differences.

Shortcut. East–west gap = 40 + 30 = 70 and north–south gap = 30 + 40 = 70; equal gaps make a square's diagonal, 70√2 km (≈ 99).

Common trap. "100 km" — seeing each bus 50 km from the depot (3-4-5) and adding 50 + 50, which assumes they went in exactly opposite directions.

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