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Easypythagoras

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Two men walking apart

Two men start from the same point. One walks 4 km north and the other 3 km east. How far apart are they?

Show the answer and the worked solution

Correct answer: B.

5 km

Worked solution

  1. Distance apart = √(4² + 3²) = 5 km.

Answer: 5 km.

The idea

Two perpendicular displacements from a common start form a right triangle whose hypotenuse is the gap between them.

Shortcut. The two paths are perpendicular legs of 4 and 3, so their ends are a 3-4-5 hypotenuse apart: 5 km.

Common trap. "1 km" — subtracting 3 from 4 as if both walked along the same line; they walked at right angles.

Two men walking apart — Direction Sense Aptitude Question

Two men walking apart: Two men start from the same point. One walks 4 km north and the other 3 km east. Answer and worked solution on CodeKairo.

Question

Two men start from the same point. One walks 4 km north and the other 3 km east. How far apart are they?

Options

  1. 1 km
  2. 5 km
  3. 7 km
  4. 12 km
Show the answer and the worked solution

Correct answer: B. 5 km

Worked solution

  1. Distance apart = √(4² + 3²) = 5 km.

Answer: 5 km.

The idea

Two perpendicular displacements from a common start form a right triangle whose hypotenuse is the gap between them.

Shortcut. The two paths are perpendicular legs of 4 and 3, so their ends are a 3-4-5 hypotenuse apart: 5 km.

Common trap. "1 km" — subtracting 3 from 4 as if both walked along the same line; they walked at right angles.

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