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Easycompound growth

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Two years of population growth

A town's population is 50,000 and grows by 10% every year. What will it be after 2 years?

Show the answer and the worked solution

Correct answer: B.

60,500

Worked solution

  1. After year 1: 50,000 × 1.1 = 55,000.
  2. After year 2: 55,000 × 1.1 = 60,500.

Answer: 60,500.

The idea

Repeated percentage growth is compound growth: multiply by (1 + r/100) once per period. Two years at 10% is a 21% rise, not 20%.

Shortcut. Add 10% twice, the second 10% also on the first year's gain: 5,000 + 5,000 + 500 = 10,500 added, giving 60,500.

Common trap. 60,000 — adding 20% as simple growth; the second year's 10% is on 55,000, not 50,000.

Two years of population growth — Aptitude Question

Two years of population growth: A town's population is 50,000 and grows by 10% every year. What will it be after 2… Answer and worked solution on CodeKairo.

Question

A town's population is 50,000 and grows by 10% every year. What will it be after 2 years?

Options

  1. 60,000
  2. 60,500
  3. 61,000
  4. 62,500
Show the answer and the worked solution

Correct answer: B. 60,500

Worked solution

  1. After year 1: 50,000 × 1.1 = 55,000.
  2. After year 2: 55,000 × 1.1 = 60,500.

Answer: 60,500.

The idea

Repeated percentage growth is compound growth: multiply by (1 + r/100) once per period. Two years at 10% is a 21% rise, not 20%.

Shortcut. Add 10% twice, the second 10% also on the first year's gain: 5,000 + 5,000 + 500 = 10,500 added, giving 60,500.

Common trap. 60,000 — adding 20% as simple growth; the second year's 10% is on 55,000, not 50,000.

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