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Easysuccessive change

~45s

Up 20%, then down 20%

A price is increased by 20% and the new price is then decreased by 20%. What is the net change from the original?

Show the answer and the worked solution

Correct answer: A.

4% decrease

Worked solution

  1. Take the original as 100. After +20%: 120. After −20% of 120: 120 − 24 = 96.
  2. Net change = 96 − 100 = −4, i.e. a 4% decrease.

Answer: 4% decrease.

The idea

Successive changes multiply: a% then b% gives a net of a + b + ab/100. An equal rise and fall of x% always nets to a loss of x²/100 percent — here 20²/100 = 4%.

Shortcut. Write it as (1 + 0.2)(1 − 0.2) = 1 − 0.2² = 0.96: a difference of squares, so an equal rise and fall always ends below the start.

Common trap. No change — assuming +20% and −20% cancel; the 20% cut is taken from the larger 120, so it removes 24.

Up 20%, then down 20% — Percentages Aptitude Question

Up 20%, then down 20%: A price is increased by 20% and the new price is then decreased by 20%. Answer and worked solution on CodeKairo.

Question

A price is increased by 20% and the new price is then decreased by 20%. What is the net change from the original?

Options

  1. 4% decrease
  2. 2% decrease
  3. No change
  4. 4% increase
Show the answer and the worked solution

Correct answer: A. 4% decrease

Worked solution

  1. Take the original as 100. After +20%: 120. After −20% of 120: 120 − 24 = 96.
  2. Net change = 96 − 100 = −4, i.e. a 4% decrease.

Answer: 4% decrease.

The idea

Successive changes multiply: a% then b% gives a net of a + b + ab/100. An equal rise and fall of x% always nets to a loss of x²/100 percent — here 20²/100 = 4%.

Shortcut. Write it as (1 + 0.2)(1 − 0.2) = 1 − 0.2² = 0.96: a difference of squares, so an equal rise and fall always ends below the start.

Common trap. No change — assuming +20% and −20% cancel; the 20% cut is taken from the larger 120, so it removes 24.

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