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Travelling at a fraction of the usual speed

Walking at three-quarters of his usual speed, a man reaches his office 20 minutes late. What is his usual time for the journey?

Show the answer and the worked solution

Correct answer: B.

60 min

Worked solution

  1. Speed × time is constant, so at 3/4 speed the time becomes 4/3 of usual.
  2. Extra time = (4/3 − 1) × usual = (1/3) × usual = 20 min.
  3. Usual time = 60 minutes.

Answer: 60 min.

The idea

At a fraction a/b of the usual speed the time becomes b/a of usual. The delay is the difference from 1, so the usual time follows in one step.

Shortcut. Back-substitute: 60 min at 3/4 speed becomes 60 × 4/3 = 80 min — exactly 20 minutes late.

Common trap. 75 min comes from taking the delay as a quarter of the usual time because the speed fell by a quarter: 20 × 4 = 80 min, nearest option 75. At 3/4 speed the time is 4/3 of usual, so the delay is a third of it: 20 × 3 = 60 min.

Travelling at a fraction of the usual speed — Aptitude

Travelling at a fraction of the usual speed: Walking at three-quarters of his usual speed, a man reaches his office… Answer and worked solution on CodeKairo.

Question

Walking at three-quarters of his usual speed, a man reaches his office 20 minutes late. What is his usual time for the journey?

Options

  1. 45 min
  2. 60 min
  3. 75 min
  4. 90 min
Show the answer and the worked solution

Correct answer: B. 60 min

Worked solution

  1. Speed × time is constant, so at 3/4 speed the time becomes 4/3 of usual.
  2. Extra time = (4/3 − 1) × usual = (1/3) × usual = 20 min.
  3. Usual time = 60 minutes.

Answer: 60 min.

The idea

At a fraction a/b of the usual speed the time becomes b/a of usual. The delay is the difference from 1, so the usual time follows in one step.

Shortcut. Back-substitute: 60 min at 3/4 speed becomes 60 × 4/3 = 80 min — exactly 20 minutes late.

Common trap. 75 min comes from taking the delay as a quarter of the usual time because the speed fell by a quarter: 20 × 4 = 80 min, nearest option 75. At 3/4 speed the time is 4/3 of usual, so the delay is a third of it: 20 × 3 = 60 min.

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