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Equal lengths, different speeds

Two trains of equal length 120 m run on parallel tracks at 42 km/h and 30 km/h in the same direction. How long does the faster take to pass the slower?

Show the answer and the worked solution

Correct answer: B.

72 s

Worked solution

  1. Relative speed = 42 − 30 = 12 km/h = 12 × 5/18 = 10/3 m/s.
  2. Distance = 240 m.
  3. Time = 240 ÷ (10/3) = 240 × 3/10 = 72 s.

Answer: 72 s.

The idea

Same direction, so subtract speeds, and the distance is both lengths together. Keeping 10/3 as a fraction avoids rounding.

Shortcut. 12 km/h is 12,000 m in 60 minutes, i.e. 200 m a minute, so the 240 m take 1.2 min = 72 s.

Common trap. 80 s — rounding the relative speed 10/3 m/s down to 3 m/s before dividing (240 ÷ 3); keeping the fraction gives 72 s.

Equal lengths, different speeds — Aptitude Question

Equal lengths, different speeds: Two trains of equal length 120 m run on parallel tracks at 42 km/h and 30 km/h in… Answer and worked solution on CodeKairo.

Question

Two trains of equal length 120 m run on parallel tracks at 42 km/h and 30 km/h in the same direction. How long does the faster take to pass the slower?

Options

  1. 60 s
  2. 72 s
  3. 80 s
  4. 90 s
Show the answer and the worked solution

Correct answer: B. 72 s

Worked solution

  1. Relative speed = 42 − 30 = 12 km/h = 12 × 5/18 = 10/3 m/s.
  2. Distance = 240 m.
  3. Time = 240 ÷ (10/3) = 240 × 3/10 = 72 s.

Answer: 72 s.

The idea

Same direction, so subtract speeds, and the distance is both lengths together. Keeping 10/3 as a fraction avoids rounding.

Shortcut. 12 km/h is 12,000 m in 60 minutes, i.e. 200 m a minute, so the 240 m take 1.2 min = 72 s.

Common trap. 80 s — rounding the relative speed 10/3 m/s down to 3 m/s before dividing (240 ÷ 3); keeping the fraction gives 72 s.

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