AI InterviewSearch…Search problems, topics, or pages…Ctrl KGet started
Hardaverage speed

~90s

A journey in three equal parts

A man covers equal distances at 10, 20 and 60 km/h. What is his average speed for the whole journey?

Show the answer and the worked solution

Correct answer: A.

18 km/h

Worked solution

  1. Take each stretch as 60 km. Times: 6 h, 3 h and 1 h.
  2. Total = 180 km in 10 h.
  3. Average = 18 km/h.

Answer: 18 km/h.

The idea

For equal distances the average is the harmonic mean 3/(1/10 + 1/20 + 1/60). Choosing the LCM of the speeds as the distance makes every time a whole number.

Shortcut. One kilometre of each stretch takes 1/10 + 1/20 + 1/60 = 1/6 h, so 3 km take 1/6 h — 18 km/h.

Common trap. 30 km/h — averaging the three speeds, (10 + 20 + 60) ÷ 3; six of the ten hours are spent at 10 km/h, so the true average is far lower.

A journey in three equal parts — Aptitude Question

A journey in three equal parts: A man covers equal distances at 10, 20 and 60 km/h. What is his average speed for… Answer and worked solution on CodeKairo.

Question

A man covers equal distances at 10, 20 and 60 km/h. What is his average speed for the whole journey?

Options

  1. 18 km/h
  2. 20 km/h
  3. 24 km/h
  4. 30 km/h
Show the answer and the worked solution

Correct answer: A. 18 km/h

Worked solution

  1. Take each stretch as 60 km. Times: 6 h, 3 h and 1 h.
  2. Total = 180 km in 10 h.
  3. Average = 18 km/h.

Answer: 18 km/h.

The idea

For equal distances the average is the harmonic mean 3/(1/10 + 1/20 + 1/60). Choosing the LCM of the speeds as the distance makes every time a whole number.

Shortcut. One kilometre of each stretch takes 1/10 + 1/20 + 1/60 = 1/6 h, so 3 km take 1/6 h — 18 km/h.

Common trap. 30 km/h — averaging the three speeds, (10 + 20 + 60) ÷ 3; six of the ten hours are spent at 10 km/h, so the true average is far lower.

All Time, Speed & Distance questions · placement mock tests