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From nine hours to ten

A cistern is normally filled in 9 hours, but a leak makes it take 10 hours. How long would the leak alone take to empty the full cistern?

Show the answer and the worked solution

Correct answer: D.

90 h

Worked solution

  1. Leak rate = 1/9 − 1/10 = 10/90 − 9/90 = 1/90.
  2. The leak alone empties it in 90 hours.

Answer: 90 h.

The idea

A small delay implies a very slow leak. When two times are close, the difference of their reciprocals is tiny and the answer is large.

Shortcut. Leak time = product ÷ difference of the two filling times: 9 × 10 ÷ (10 − 9) = 90 hours.

Common trap. 45 h — half of 9 × 10, from dividing by 2 as if the delay were two hours; with a one-hour gap, product ÷ difference = 90 ÷ 1.

From nine hours to ten — Time & Work Aptitude Question

From nine hours to ten: A cistern is normally filled in 9 hours, but a leak makes it take 10 hours. Answer and worked solution on CodeKairo.

Question

A cistern is normally filled in 9 hours, but a leak makes it take 10 hours. How long would the leak alone take to empty the full cistern?

Options

  1. 45 h
  2. 60 h
  3. 75 h
  4. 90 h
Show the answer and the worked solution

Correct answer: D. 90 h

Worked solution

  1. Leak rate = 1/9 − 1/10 = 10/90 − 9/90 = 1/90.
  2. The leak alone empties it in 90 hours.

Answer: 90 h.

The idea

A small delay implies a very slow leak. When two times are close, the difference of their reciprocals is tiny and the answer is large.

Shortcut. Leak time = product ÷ difference of the two filling times: 9 × 10 ÷ (10 − 9) = 90 hours.

Common trap. 45 h — half of 9 × 10, from dividing by 2 as if the delay were two hours; with a one-hour gap, product ÷ difference = 90 ÷ 1.

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