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Hardaverage speed

~105s

Half the distance at each speed

A man covers half a journey at 30 km/h and the other half at 20 km/h, taking 10 hours in all. What is the total distance?

Show the answer and the worked solution

Correct answer: C.

240 km

Worked solution

  1. (d/2)/30 + (d/2)/20 = 10 → d/60 + d/40 = 10.
  2. Common denominator 120: 2d/120 + 3d/120 = 10 → 5d/120 = 10.
  3. d = 240, so the journey is 240 km.

Answer: 240 km.

The idea

Write the time for each half in terms of the whole distance and add. The average speed here is 24 km/h, and 24 × 10 = 240 confirms it.

Shortcut. Back-substitute: 240 km means 120 km at 30 km/h (4 h) plus 120 km at 20 km/h (6 h) — exactly 10 h.

Common trap. Averaging the speeds to 25 km/h gives 25 × 10 = 250 km; with equal distances the average speed is the harmonic mean, 2 × 30 × 20 ÷ 50 = 24 km/h, and that is the speed to multiply by the 10 hours.

Half the distance at each speed — Aptitude Question

Half the distance at each speed: A man covers half a journey at 30 km/h and the other half at 20 km/h, taking 10… Answer and worked solution on CodeKairo.

Question

A man covers half a journey at 30 km/h and the other half at 20 km/h, taking 10 hours in all. What is the total distance?

Options

  1. 200 km
  2. 220 km
  3. 240 km
  4. 260 km
Show the answer and the worked solution

Correct answer: C. 240 km

Worked solution

  1. (d/2)/30 + (d/2)/20 = 10 → d/60 + d/40 = 10.
  2. Common denominator 120: 2d/120 + 3d/120 = 10 → 5d/120 = 10.
  3. d = 240, so the journey is 240 km.

Answer: 240 km.

The idea

Write the time for each half in terms of the whole distance and add. The average speed here is 24 km/h, and 24 × 10 = 240 confirms it.

Shortcut. Back-substitute: 240 km means 120 km at 30 km/h (4 h) plus 120 km at 20 km/h (6 h) — exactly 10 h.

Common trap. Averaging the speeds to 25 km/h gives 25 × 10 = 250 km; with equal distances the average speed is the harmonic mean, 2 × 30 × 20 ÷ 50 = 24 km/h, and that is the speed to multiply by the 10 hours.

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