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Two cars, same road

Two cars cover the same distance, one at 45 km/h and the other at 60 km/h. The slower takes 1 hour longer. What is the distance?

Show the answer and the worked solution

Correct answer: C.

180 km

Worked solution

  1. d/45 − d/60 = 1.
  2. Common denominator 180: 4d/180 − 3d/180 = 1 → d/180 = 1.
  3. d = 180 km.

Answer: 180 km.

The idea

Difference of times equals the stated delay. The common denominator of the two speeds is usually the distance itself, which is a handy check.

Shortcut. Distance = (product of speeds ÷ difference of speeds) × time gap = (2,700 ÷ 15) × 1 h = 180 km.

Common trap. Subtracting the denominators — taking 1/45 − 1/60 as 1/15 — gives d = 15 km; the true difference is 4/180 − 3/180 = 1/180, so the one-hour gap is d/180.

Two cars, same road — Aptitude Question

Two cars, same road: Two cars cover the same distance, one at 45 km/h and the other at 60 km/h. Answer and worked solution on CodeKairo.

Question

Two cars cover the same distance, one at 45 km/h and the other at 60 km/h. The slower takes 1 hour longer. What is the distance?

Options

  1. 120 km
  2. 150 km
  3. 180 km
  4. 200 km
Show the answer and the worked solution

Correct answer: C. 180 km

Worked solution

  1. d/45 − d/60 = 1.
  2. Common denominator 180: 4d/180 − 3d/180 = 1 → d/180 = 1.
  3. d = 180 km.

Answer: 180 km.

The idea

Difference of times equals the stated delay. The common denominator of the two speeds is usually the distance itself, which is a handy check.

Shortcut. Distance = (product of speeds ÷ difference of speeds) × time gap = (2,700 ÷ 15) × 1 h = 180 km.

Common trap. Subtracting the denominators — taking 1/45 − 1/60 as 1/15 — gives d = 15 km; the true difference is 4/180 − 3/180 = 1/180, so the one-hour gap is d/180.

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