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Hardtrains

~105s

Two trains, one pole

A train passes a pole in 15 seconds and a platform 100 m long in 25 seconds. What is the length of the train?

Show the answer and the worked solution

Correct answer: B.

150 m

Worked solution

  1. L = 15v and L + 100 = 25v.
  2. Subtracting: 100 = 10v → v = 10 m/s.
  3. L = 15 × 10 = 150 m.

Answer: 150 m.

The idea

Two crossing times give two equations in length and speed. Subtracting eliminates the length and hands you the speed immediately.

Shortcut. The platform adds 10 s to the pole's 15 s, so train : platform = 15 : 10 and the train is 1.5 × 100 = 150 m.

Common trap. Stopping at 25v = 25 × 10 = 250 m gives the train plus the platform; the train alone is what passes the pole, so its length is the 15 seconds' run at 10 m/s.

Two trains, one pole — Aptitude Question

Two trains, one pole: A train passes a pole in 15 seconds and a platform 100 m long in 25 seconds. Answer and worked solution on CodeKairo.

Question

A train passes a pole in 15 seconds and a platform 100 m long in 25 seconds. What is the length of the train?

Options

  1. 120 m
  2. 150 m
  3. 180 m
  4. 200 m
Show the answer and the worked solution

Correct answer: B. 150 m

Worked solution

  1. L = 15v and L + 100 = 25v.
  2. Subtracting: 100 = 10v → v = 10 m/s.
  3. L = 15 × 10 = 150 m.

Answer: 150 m.

The idea

Two crossing times give two equations in length and speed. Subtracting eliminates the length and hands you the speed immediately.

Shortcut. The platform adds 10 s to the pole's 15 s, so train : platform = 15 : 10 and the train is 1.5 × 100 = 150 m.

Common trap. Stopping at 25v = 25 × 10 = 250 m gives the train plus the platform; the train alone is what passes the pole, so its length is the 15 seconds' run at 10 m/s.

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