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Hardefficiency

~105s

Twenty-five percent more efficient

A is 25% more efficient than B and takes 10 days less to finish a job. How many days does A take?

Show the answer and the worked solution

Correct answer: B.

40

Worked solution

  1. A's time = B's time ÷ 1.25 = 0.8 × B's time.
  2. t − 0.8t = 10 → 0.2t = 10 → t = 50.
  3. B takes 50 days, so A takes 0.8 × 50 = 40 days.

Answer: 40 days.

The idea

Efficiency and time are inversely proportional: 25% more efficient means 20% less time. Converting the percentage correctly is the crux.

Shortcut. Efficiency 5 : 4 means time 4 : 5, so the 10-day gap is one part and A takes 4 × 10 = 40 days.

Common trap. 50 — B's time, the first number the equation 0.2t = 10 produces; A takes 0.8 × 50.

Twenty-five percent more efficient — Aptitude Question

Twenty-five percent more efficient: A is 25% more efficient than B and takes 10 days less to finish a job. Answer and worked solution on CodeKairo.

Question

A is 25% more efficient than B and takes 10 days less to finish a job. How many days does A take?

Options

  1. 30
  2. 40
  3. 45
  4. 50
Show the answer and the worked solution

Correct answer: B. 40

Worked solution

  1. A's time = B's time ÷ 1.25 = 0.8 × B's time.
  2. t − 0.8t = 10 → 0.2t = 10 → t = 50.
  3. B takes 50 days, so A takes 0.8 × 50 = 40 days.

Answer: 40 days.

The idea

Efficiency and time are inversely proportional: 25% more efficient means 20% less time. Converting the percentage correctly is the crux.

Shortcut. Efficiency 5 : 4 means time 4 : 5, so the 10-day gap is one part and A takes 4 × 10 = 40 days.

Common trap. 50 — B's time, the first number the equation 0.2t = 10 produces; A takes 0.8 × 50.

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