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Mediumefficiency

~60s

Twice as fast

A works twice as fast as B. Together they finish a job in 12 days. How long would B alone take?

Show the answer and the worked solution

Correct answer: D.

36 days

Worked solution

  1. Let B's rate be 1 unit/day; then A's is 2, and together 3 units/day.
  2. Total work = 3 × 12 = 36 units.
  3. B alone: 36 ÷ 1 = 36 days.

Answer: 36 days.

The idea

Efficiency ratios become rate ratios directly. Set the slowest rate to 1 unit and everything else follows without fractions.

Shortcut. B supplies 1 of the pair's 3 shares of output, so alone B needs 3 × 12 = 36 days (and A needs 1.5 × 12 = 18).

Common trap. 18 days — A's time alone; A is the faster worker, while the question asks about B.

Twice as fast — Time & Work Aptitude Question

Twice as fast: A works twice as fast as B. Together they finish a job in 12 days. How long would B alone take? Answer and worked solution on CodeKairo.

Question

A works twice as fast as B. Together they finish a job in 12 days. How long would B alone take?

Options

  1. 18 days
  2. 24 days
  3. 30 days
  4. 36 days
Show the answer and the worked solution

Correct answer: D. 36 days

Worked solution

  1. Let B's rate be 1 unit/day; then A's is 2, and together 3 units/day.
  2. Total work = 3 × 12 = 36 units.
  3. B alone: 36 ÷ 1 = 36 days.

Answer: 36 days.

The idea

Efficiency ratios become rate ratios directly. Set the slowest rate to 1 unit and everything else follows without fractions.

Shortcut. B supplies 1 of the pair's 3 shares of output, so alone B needs 3 × 12 = 36 days (and A needs 1.5 × 12 = 18).

Common trap. 18 days — A's time alone; A is the faster worker, while the question asks about B.

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