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Hardequivalenceman-days

~150s

Men, women and hours

15 men take 21 days of 8 hours each to do a piece of work. How many days of 6 hours each would 21 women take, if 3 women do as much work as 2 men?

Show the answer and the worked solution

Correct answer: C.

30

Worked solution

  1. Total work = 15 × 21 × 8 = 2,520 man-hours.
  2. 3 women ≡ 2 men, so 21 women ≡ 14 men.
  3. Daily output = 14 × 6 = 84 man-hours.
  4. Days = 2,520 ÷ 84 = 30 days.

Answer: 30 days.

The idea

Convert the workforce into one unit first, then work in that unit's hours throughout. Attempting to convert at the end mixes incompatible quantities.

Shortcut. 21 women = 14 men. Days = 21 × 15/14 × 8/6; 21/14 = 3/2 and 15 × 8/6 = 20, so 3/2 × 20 = 30.

Common trap. 20 — counting the 21 women as 21 men (21 × 15/21 × 8/6 = 20); they are worth only 14 men.

Men, women and hours — Time & Work Aptitude Question

Men, women and hours: 15 men take 21 days of 8 hours each to do a piece of work. How many days of 6 hours each… Answer and worked solution on CodeKairo.

Question

15 men take 21 days of 8 hours each to do a piece of work. How many days of 6 hours each would 21 women take, if 3 women do as much work as 2 men?

Options

  1. 20
  2. 25
  3. 30
  4. 36
Show the answer and the worked solution

Correct answer: C. 30

Worked solution

  1. Total work = 15 × 21 × 8 = 2,520 man-hours.
  2. 3 women ≡ 2 men, so 21 women ≡ 14 men.
  3. Daily output = 14 × 6 = 84 man-hours.
  4. Days = 2,520 ÷ 84 = 30 days.

Answer: 30 days.

The idea

Convert the workforce into one unit first, then work in that unit's hours throughout. Attempting to convert at the end mixes incompatible quantities.

Shortcut. 21 women = 14 men. Days = 21 × 15/14 × 8/6; 21/14 = 3/2 and 15 × 8/6 = 20, so 3/2 × 20 = 30.

Common trap. 20 — counting the 21 women as 21 men (21 × 15/21 × 8/6 = 20); they are worth only 14 men.

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